I have done it again

[CAP]

Ok I am once again doing another small and useless test so please don't ask me why I have printed what I have I just did so..

#include <stdio.h>

int userNum;
int x=1;

int main(void)
{
	printf("Please enter the number 1: ");
	scanf("%d", &userNum);

	{
	if(userNum != x)
	
		printf("Hey! I told you to type the number 1 not %d\n\n", userNum);

		else
			printf("Thank you for followind my instructions\n\n");
	}
	
	do
{
	printf("This is the do part");
} while(userNum>1; x--); /*this is it*/

	do 
{
    printf("ndlfasdf");
} while ( x > 0 );
	


	return 0;
}

The do while statement that has the comment [this is it] beside it, I don't know why it won't work, the one under it is from my compilers index I was comparing them so what is wrong with mine, I know it looks wrong but my compiler just says I have 2 errors, I need to put some brackets in but they only make more problems.

[Cshot]

Like this:

#include <stdio.h>

int userNum;
int x=1;

int main(void)
{
   printf("Please enter the number 1: ");
   scanf("%d", &userNum);

   if(userNum != x)
      printf("Hey! I told you to type the number 1 not %d\n\n",  userNum);
   else
      printf("Thank you for followind my instructions\n\n");
	
   do
   {
      printf("This is the do part");
      x--;
   } while(userNum>1); /*this is it*/

   do 
   {
      printf("ndlfasdf");
   } while ( x > 0 );
	
   return 0;
}

You had mismatching braces and your
while(userNum>1; x--);
is invalid syntax.

[CAP]

Ok thank you, I wasn't sure of how to set up the do while corretly, thanks.