problem with my array question

Hi i am back with another question :)....

6.10 Use a single subscript array to sove the following problem.A company pays its sales people on a comision basis.The salespeople recive $200 per week plus 9 percent of their gross sales for that week.For example, a salesperson whos grosses $3000 in sales in a week receives $200 plus 9 percent of $3000, or a total of $470.Write a c program ( ussing a counter of arrays) that determines how many of the salespeople earned salaries in each of the following ranges ( assume that each salesperson's salary is truncated to an integer amount).

1.200-299
2.300-399
3.400-499
4.500.599

and so on ..

Okay the question is.What do they mean by Using a counter of arrays and assume that each persons salary is truncated to an integer amount.

A counter array:

int paybracket[SOME_SIZE] = {0};

Where paybracket[0] represents the first pay slot, paybracket[1] equals the next range, and so on.

Thus, when ted shows up, you simply find what bracket his pay goes in and increment that spot:

paybracket[x]++;

I could give you the formulate to find where his pay falls, but it's so easy, you should be able to figure it out.

Quzah.

Is this what u mean by a counter array ..

Code:

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#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define SIZE 7

int main()
{
  int face, roll, frequency[ SIZE ] = { 0 };   

  srand( time( NULL ) );

  for ( roll = 1; roll <= 6000; roll++ ) {
      face = rand() % 6 + 1;
      ++frequency[ face ];    } 

  printf( "%s%17s\n", "Face", "Frequency" );

  for ( face = 1; face <= SIZE - 1; face++ )
      printf( "%4d%17d\n", face, frequency[ face ] );

  return 0;
}

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Like in this code i could have used a switch statment right, but i used an array..Is this what u call an array counter????I.f this is the method I have tried my level best and i am still stuck need some help..

Quote:

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face = rand() % 6 + 1;
++frequency[face]; }

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Do you see your problem? If not, answer two questions:

1) What is the valid range of face?
2) What is the valid range of frequency's indexing?

Arrays go from 0 to size-1. As such, you're going out of bounds of your array. Lose the "+1" and it should work fine.

And yes, that's what I meant by a counter array. Basicly it's an array who's indexes store a count value for a range of counters.

Quzah.

Yo Q..I was refering to the question 6.10) that i asked in the beginning in the post ..I cant do it i have tried every thing but ??I dont know ..help me out ..The problwm is that how can i say that
++array [ 200 <= 299 ] ????

It's an easy formulae. You just have to think about it. Very simple stuff. Analyze your pattern:

Quote:

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1.200-299
2.300-399
3.400-499
4.500.599

---

Ok, so we start at 200. This means that our first cell must represent the first range, which is 200-299.

To make sure the values line up right with the bucket (each bucket holding a range of 100 numbers), you should subtract 200 from the initial value.

Now then, to ignore the last two digits of the data, how about dividing by 100? That makes sense, right?

Say I input 303.

303 - 200 = 103
103 / 100 = 1

Thus:

array[1]++;

See? Like I said, if you put a few minutes thought into it, the forumlae is simple.

Quzah.

I found the formula...but i guess urs is better

hear

Code:

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int y = (total)/100;
++a[y-2];

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If total is 499 it removes the 2nd last integers and now y is 4 then y-2 gives us 2 which means ++a[2]; is incremented ..how was that ..

Code:

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#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#define SIZE 9

int main()
{
 int a[SIZE]= {0};
 int  total1,total, gross, sal=200, y;

 printf ( "Enter you gross sales in a week:$ ");
 scanf ("%d", &gross );
 while ( gross != -1 ){
 total1 = (gross * 9) /100;
 total = total1 +sal;
  y = floor ( total ) /100;
 ++a[y-2];
 printf ("Enter your gross sales in a week:$ ");
 scanf ( "%d", &gross );
 }

 printf ("According to the price\n");
 printf (" 200-299: %d\n"
        " 300-399: %d\n"
        " 400-499: %d\n"
        " 500-599: %d\n"
        " 600-699: %d\n"
        " 700-799: %d\n"
        " 800-899: %d\n"
        " 900-999: %d\n"
        " 1000 and above: %d", a[0], a[1], a[2], a[3], a[4], a[5], a[6],a[7], a[8]);


      system("PAUSE");
      return 0;
}

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