this is a simple p[rogram that i hope has a simple answer?

Hi!
I am suppose to write a code that uses this char declaration and its suppose to print out values that can tell me how many bytes are alloted for each variables?

My answer is 1 bytes. Is that correct since there are 4 bits to one byte or is it 8 bits?

Code:

#include<stdio.h>

int main()
{
	char  a, b, c, *p, *q, *r;

		printf("%p\n%p\n%p\n", a, b, c);
		printf("%p\n%p\n%p\n", *p, *q, *r);

		return 0;
}

It's 8 bits to a byte.

>printf("%p\n%p\n%p\n", a, b, c);
Isn't printing the size of the variables. To do that you need the sizeof operator.

Code:

#include <stdio.h>

int main(void)
{
    char    a, *p;

    printf("sizeof(a) : %d\n", sizeof(a));
    printf("sizeof(p) : %d\n", sizeof(p));

    return(0);
}

Note that pointers take up more than 1 char (on my system they take up 4). This number represents the size of the pointer itself, not the size of the data that the pointer is pointing to.