size of array

[Unregistered]

How i can find the size of array?! for example i have the program below and i want to replace the number 4 with the array size! thanks 4 any help!

#include <stdio.h>
int main ()
{
char str []="MORAL"; int i, j;
puts ("\n");
for (i=0; i <= 4; i++)
{
for (j=i+1; j <= 4; j++)
printf ("{%c, %c}\n",str[i],str[j]);
}
return 0;
}

[Govtcheez]

> How i can find the size of array?!

sizeof(str)

Alternatively, if the string is smaller than the array (which it isn't, in your case), then

#include <string.h>

strlen(str);

[Monster]

Originally posted by Govtcheez
Alternatively, if the string is smaller than the array (which it isn't, in your case) ...

The string is not smaller but strlen doesn't count the null character...

[Salem]

The size of the array is given by
sizeof(arr)

To count the number of valid subscripts of the array, its
sizeof( arr ) / sizeof( arr[0] )

I use this macro quite a lot

#define ASIZE(x) (sizeof(x)/sizeof(x[0]))

Then I can do
for ( i = 0 ; i < ASIZE(arr); i++ ) arr[i] = 0;

[Govtcheez]

> The string is not smaller but strlen doesn't count the null character...

Yeah, I think I said that when I said it wasn't, in his case.

I meant a situation like

char s[100] = "yo";

sizeof returns 100 (assuming a 1 byte char), while strlen returns 2.