What's wrong?

[Paninaro]

Compiler says:
-two or more data types in declaration of `presentar'
-conflicting types for 'presentar'
-previous declaration of 'presentar'

What's wrong in my program??

#include <stdio.h>

union byte{
  unsigned char byte;
  struct{
    unsigned char b0:1;
    unsigned char b1:1;
    unsigned char b2:1;
    unsigned char b3:1;
    unsigned char b4:1;
    unsigned char b5:1;
    unsigned char b6:1;
    unsigned char b7:1;
  }bits;
}

void presentar(unsigned char c);
unsigned char reflejarbyte(union byte b);

main(void)
{
  union byte b;
  
  printf("Introduzca un caracter: ");
  b.byte=getchar();
  presentar(b.byte);
  
  b.byte=reflejarbyte(b);
  printf("Caracter reflejado: %c\n",b.byte);
  presentar(b.byte);
}

void presentar(unsigned char c)
{
  int i=0;
  
  printf("El valor ASCII de %c es %Xh; en binario:",c,c);
  for(i=7;i>=0;i--)
    printf("%d",(c&(1<<i))?1:0);
  printf("\n");
}

unsigned char reflejarbyte(union byte b)
{
  union byte c;
  
  c.bits.b0=b.bits.b7;
  c.bits.b1=b.bits.b6;
  c.bits.b2=b.bits.b5;
  c.bits.b3=b.bits.b4;
  c.bits.b4=b.bits.b3;
  c.bits.b5=b.bits.b2;
  c.bits.b6=b.bits.b1;
  c.bits.b7=b.bits.b0;
  
  return (c.byte);
}

[Prelude]

union byte{
  unsigned char byte;
  struct{
    unsigned char b0:1;
    unsigned char b1:1;
    unsigned char b2:1;
    unsigned char b3:1;
    unsigned char b4:1;
    unsigned char b5:1;
    unsigned char b6:1;
    unsigned char b7:1;
  }bits;
}; /* Don't forget the semicolon */

-Prelude

[quzah]

You can reverse the bits using a loop too...

#define O unsigned char
O x0(O x00){O x01=0x00;int x;for(x=
0x00;x<sizeof(O)<<0x03;x+=0x01){if
(x00&0x01<<x)x01|=(0x01<<(((sizeof
(O)<<0x03)-0x01)-x));}return x01;}

Quzah.