Thread: Question on for loop

#include <stdio.h>
#include <string.h> //for strlen()
#include <stdlib.h> //for atoi()
#include <conio.h> //for getch()

#line 1 /* makes the first line: 'void main(...)' help Debuging process. good programming pratice */
void main (int argc, char **argv){

unsigned short n, age;
n = strlen(argv[1]);
age = atoi(argv[2]);
if (n < 5) {
printf("Your name is short\n");
}
if(n > 5){
printf("Your name is long\n");
}
if(age > 20){
for (; age <= 100; ++age){
printf("boy are you OLD!\n");
}
}else{
printf("boy you're YOUNG\n");
}
getch();
}[FONT=arial]

> 'void main(...)'
God, don't use that.

My compiler screams at me for even having it in there.

[edit]
Pleaase use code tags.
Use int main(void)
return 0; at the end of main.
...and if you think void main is good, please don't help anybody.
[/edit]

anatazi, possibly you could refer to this for command line stuff:

Code:

/*

	Program:
	CmdLine.c
	
	Purpose:
	Demonstrates the use of command line parameters.

*/

#include <stdio.h>

void default_message(void);

int main( int argc, char * argv[] )  
{
	if (argc == 2)
	{
		if(argv[1][0] == '?')
		{
			printf("Help stuff would go here.\n");
		}
		else
		{
			printf("%s \n", argv[1]);
		}
	}
	else if ( argc >= 3 )
	{
		printf("Invalid input:\n");
		printf("Only one command-line parameter allowed.\n");
	}
	else
	{
		default_message();
	}
	return 0;
}

void default_message(void)
{
	printf("CmdLine.exe:\n");
	printf("The purpose of this program is to demonstrate command line arguments.\n");
	printf("This program will print whatever you type on the screen.\n\n");
	printf("Example:\n");
	printf("C:\\>CmdLine.exe Hmmm\n");
	printf("Hmmm\n");
}

This just demonstrates command line arguments, i'll leave the age stuff to you.