i have the following snippet of code
i get an error that guesses may not be initializedCode:char pword[] = "hel"; int plen = strlen( pword );// plen = 3 ..... int guesses[plen][26] = { 0 }; ....
however if i haveno errorCode:int guesses[3][26] = { 0 }
In C the sizes of arrays must be compile time constants. If you want to use non-compile-time constants for the array size you must use manual memory management with malloc/free.
@jim, You are forgetting about variable-length arrays (which are only optionally available pre-C23).
@D.B., The second has constant dimensions whereas the first uses a variable.
You are not allowed to initialize a variable-length array (I'm not sure why).
However, you can simply use
which is basically what the zero initialization automatically does anyway.Code:memset(guesses, 0, sizeof guesses); // include <string.h>
A little inaccuracy saves tons of explanation. - H.H. Munro
I take it you have dubbed me D.B. Cooper in your mind. Its along story but cooper came from Alice Cooper which used to cause great confusion as i am male but D.B is fine as its actualy my initials backwards!
in reference to the thread in the end i just did what you did and used sizeof pword which is what i was cycling through anyways
Actually I'm not forgetting, I just consider VLA an abomination.@jim, You are forgetting about variable-length arrays (which are only optionally available pre-C23).
At least one nice thing came with VLA support: you can pass array dimensions as function parameters. For example:Originally Posted by jimblumberg
And now you can pass any 2-dimensional array of int to foo.Code:int foo(int x, int y[][x]);
