It is not Runnig
Hi:
I did cut and paste this example from a tuterial and I was hoping that it will work. But my compiler, miracle C, did not even give me an error message. it just did not let it run. Will appriciate your help.
Sam
main()
{
float cost,tax,luxury,total;
luxury=0.0;
printf("Enter the cost of the item: ");
scanf("%f", &cost);
tax=cost*0.06;
if(cost>40000.0)
luxury=cost*0.005;
total=cost+tax+luxury;
printf("the total cost is %0.2f",total);
}
Don't use scanf. What you can do is use fgets to store the input into a char array and then turn this into a float using atof.
- SeanCode:int main() { float cost, tax, luxury, total; char Input[128]; luxury = 0; printf("Enter the cost of the item:"); fgets(Input, 128, stdin); cost = atof(Input); tax=cost*0.06; if(cost>40000.0) luxury=cost*0.005; total=cost+tax+luxury; printf("the total cost is %0.2f",total); return 0; }
If cities were built like software is built, the first woodpecker to come along would level civilization.
Black Frog Studios
Seems OK to me
The only minor suggestion would be
printf("the total cost is %0.2f",total);
to
printf("the total cost is %0.2f\n",total);
i got some warnings, but it works good. heres the program with the problems fixed.
PHP Code:#include <stdio.h>
void main()
{
float cost,tax,luxury,total;
luxury=0.0;
printf("Enter the cost of the item: ");
scanf("%f", &cost);
tax=cost*0.06f;
if(cost>40000.0)
{
luxury=cost*0.005f;
}
total=cost+tax+luxury;
printf("the total cost is %0.2f",total);
}
Was OK up to the void main bit
main()
or the more preferred
int main()
Is the only way to go
If you feel you must use scanf(), check it's return code to ensure it did it's job before you use the variables.
When all else fails, read the instructions.
If you're posting code, use code tags: [code] /* insert code here */ [/code]
