command line argv argc help?

[Unregistered]

how do i access the array within argv, this is what i have so far
say if i typed this at the command prompt: hw6 -fl john smith 12/20/2001, it should go to the word smith and capitalize the first letter and prints it Smith. Also, loops the whole thing and do it again and again if there are more then 1 name.

if (((cOption1 == FLCAPITALIZED) && (cOption2 == LASTNAME)) ||
((cOption2 == FLCAPITALIZED) && (cOption1 == LASTNAME))) {

do {

a = x * j;
last[0] = ((argv[a][1]) - 32);

for (i = 2; i < 40; i++) {
last[i] = (argv[a][i]);

}

printf ("%s\n", last[i]);

j++;

} while ((argv[a+2]) != '\0');

}

Thank You

[Unregistered]

anyother way i thought of is, i have

int formatName (char *cpFirstName, char *cpLastName, char *cpFullName);

and being passing the arguments

formatName (argv[y], argv[p], u);

it will return u as the whole full name as Smith, John.

How do i extract the word Smith out from u?

Thanks

[sean345]

>How do i extract the word Smith out from u?

If you know the name is written as Smith, John then you can just copy the string into another string until you come across a comma. Or you can copy the name to another string until you come across a space:

while(Pos<strlen(String)&&String[Pos]!=','){
     New[Loc++] = String[Pos++];
}
New[Loc] = '\0';

This will load from String to New until it comes across a comma.

>how do i access the array within argv?

argv[0] is the first string. The first letter in the first string is argv[0][0]. argc tells you how many strings are present and the strlen(argv[0]) will tell you how many charectors are in the first word in the command line.

- Sean

[Unregistered]

thanks sean, but my problem is i don't know what the name will be, john smith is just an example.

can you also explain more about

code:--------------------------------------------------------------------------------
while(Pos<strlen(String)&&String[Pos]!=','){
New[Loc++] = String[Pos++];
}
New[Loc] = '\0';
--------------------------------------------------------------------------------

also thanks, for explaining how to use argv and argc, but what i am trying to do is like for example smith is argv[4] and within that is the word smith, how do i access that a CAP the S and print the rest.

[Unregistered]

anothing thing is i can't use the string library to do this.... :-(

[Unregistered]

this is what i came up with so far, but it freezes and won't do anything, please help

do {

p = y + 1;

formatName (argv[y], argv[p], u);

for (i = 0; i < 40; i++) {

while (u[i] != ',') {

last[i] = u[i];

}
}

printf ("%s", last);

for (i=0; i < 40; i++) {

u[i] = SPACE;

}

y = y + 3;

} while ((argv[p+2]) != '\0');

[Hammer]

Does this help explain?

#include <stdio.h>

int main(int argc, char *argv[])
{
	int i;
	
	/* remember, argv[0] is the program name */
	for (i = 1; i < argc; i++)
		printf("Arg %d is %s, the first char is %c\n", i, argv[i], argv[i][0]);
	
	return (0);
}

/* 
c:\>junk1 my name is john
Arg 1 is my, the first char is m
Arg 2 is name, the first char is n
Arg 3 is is, the first char is i
Arg 4 is john, the first char is j
*/