Thread: Array

Hi, I'm new at C Programming. I need to find even numbers that are inserted by the user then to select the numbers which can be diveded by 6 and then to multiply those numbers.



As you can see I need to multiply 12 and 18, but i dont know how. ( Sorry for a foreign language in the image). Can someone tell me how?

Code:

#include <stdio.h>

int main()
{
    int a[50], i, n, p;


//  Vector size
    printf("Introduceti marimea vectorului:\n");
    scanf ("%d", &n);
    printf("\n");


//  Elements added by the user
    printf("Introduceti valorile elementelor:\n");
    for   (i=0; i<n; i++)
    {
        scanf("%d", &a[i]);
    }
    printf("\n");


//  Even numbers
    printf("Numerele pare din vector sunt:\n\n");
    for (i=0; i<n; i++)
    {
        if (a[i] % 2 == 0)
        {
            printf("%d\t", a[i]);
        }
    }


//  Even numbers that can be divided by 6 ( + i need to multiply those numbers)
    printf("\n\nNumerele pare care se impart la 6 fara rest sunt:\n\n");
    for (i=0; i<n; i++)
    {
        if (a[i] % 6 == 0)
        {
            printf("%d\t", a[i]);
        }
    }






    printf("\n\n\n");




    return 0;
}

p.s. And I am sorry for my english. Have a nice day!

I would suggest creating a variable to keep a running product. Whenever an array value is divisible by 6, multiply the product variable by that array value. Be sure the product variable is initialized, and to a sensible value.