Hi, I'm having trouble understanding the answer to this question. What is the value of x after this code?
int x = 1;
if (x == 1)
x = x + 1;
else
x = x + 3;
x = 3 * x;
So if I am understanding this correctly, initially x=1, it goes through the if loop and checks if x is 1, if it is, then the new x is equal to 1+1=2. but i am confused on the else part. Can someone please explain to me what happens? Thank you.
Your understanding of the "if()" part is correct. The "else" will not occur unless the "if()" condition is false (which it will not be in the given example).
I would suggest you try compiling and running this code to see what the actual output will be, using different values for "x". See if the output is what you expect.
Also note that "if()" is not a loop.
ok so after the if statement the new x becomes 2? and then it goes through the if statement again. This time the if statement is false, so it goes to the else statement and x=2+3=5, and then the statement would be x=2*3=6?
As I said, the "if()" statement is not a loop, so in the code you posted, it is only executed once.
Also be aware that the last line is not part of the "if-else", so that line is always executed.
In fact, this is what the code should look like with proper indentation, to emphasize the flow of logic:
Code:int x = 1; if (x == 1) x = x + 1; else x = x + 3; x = 3 * x;
thank you for your clarification! i get it now, so since x=1 the if statement evaluates true then x=1+1=2. so it won't even go through the else statement. therefore, x=3*2=6 after these lines of code. thanks!
