New with 2D array

This is a discussion on New with 2D array within the C Programming forums, part of the General Programming Boards category; if i have 2D array char info [2][8]; [2 9 0 5 J O H N] [3 5 5 2 ...

  1. #1
    Unregistered
    Guest

    New with 2D array

    if i have 2D array char info [2][8];
    [2 9 0 5 J O H N]
    [3 5 5 2 1 i a n ]
    if i want to show [0][1]
    it should show '9'

    i tried this one puts(info[0][1]);
    it didn't seem to work

    any idea?
    cheers

  2. #2
    ....
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    This should work: printf ("%c\n", info [0][1]);

  3. #3
    Unregistered
    Guest
    thanks
    how can i copy it to another variable
    i used like this but doesn't seem to be working

    char temp[4];

    for i=0;i<4;i++
    strcpy(temp,info[0][i]);

    should put [i] after temp?
    i also tried temp[i]=info[0][i]; the value doesn't go through i think

    any suggestion?
    cheers mate

  4. #4
    End Of Line Hammer's Avatar
    Join Date
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    6,231

    Re: New with 2D array

    Originally posted by Unregistered
    if i have 2D array char info [2][8];
    [2 9 0 5 J O H N]
    [3 5 5 2 1 i a n ]
    Just a small point...... If you are using these array as strings, you need to create the rows 1 longer than the string itself to allow for the NULL terminator.

    As for copying parts of a string, you can do this a few ways. One is to use strncpy(), which allows you to copy upto n characters from one char array to another (just watch out the the null terminator that isn't necessary appended to the target). Or you can make a bit of code to do the copy yourself. Something like
    Code:
    for (i = 0; i < 4; i++)
    	target[i] = source[i];
    Again, you will need to take care of NULL terminator if you intend to use these as strings.

    [EDIT] In your case, the source array in my sample code would be coded like this: source[0][i]
    The 0 would be replaced with the relevant index number for the string you want to work with. Here's a working example:
    Code:
    #include <stdio.h>
    int main(void)
    {
    	int i;
    	
    	char *source[] = {"abcdefgh", "ijklmnop"};
    	char target[100];
    	
    	for (i = 0; i < 4; i++)
    		target[i] = source[0][i];
    	target[i] = '\0';
    	
    	printf("source[0]: %s\n", source[0]);
    	printf("target: %s", target);
    	
    	return (0);
    }
    Last edited by Hammer; 05-04-2002 at 07:51 PM.
    When all else fails, read the instructions.
    If you're posting code, use code tags: [code] /* insert code here */ [/code]

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