New with 2D array

if i have 2D array char info [2][8];
[2 9 0 5 J O H N]
[3 5 5 2 1 i a n ]
if i want to show [0][1]
it should show '9'

i tried this one puts(info[0][1]);
it didn't seem to work

any idea?
cheers

This should work: printf ("%c\n", info [0][1]);

thanks
how can i copy it to another variable
i used like this but doesn't seem to be working

char temp[4];

for i=0;i<4;i++
strcpy(temp,info[0][i]);

should put [i] after temp?
i also tried temp[i]=info[0][i]; the value doesn't go through i think

any suggestion?
cheers mate

Originally posted by Unregistered
if i have 2D array char info [2][8];
[2 9 0 5 J O H N]
[3 5 5 2 1 i a n ]

Just a small point...... If you are using these array as strings, you need to create the rows 1 longer than the string itself to allow for the NULL terminator.

As for copying parts of a string, you can do this a few ways. One is to use strncpy(), which allows you to copy upto n characters from one char array to another (just watch out the the null terminator that isn't necessary appended to the target). Or you can make a bit of code to do the copy yourself. Something like

Code:

for (i = 0; i < 4; i++)
	target[i] = source[i];

Again, you will need to take care of NULL terminator if you intend to use these as strings.

[EDIT] In your case, the source array in my sample code would be coded like this: source[0][i]
The 0 would be replaced with the relevant index number for the string you want to work with. Here's a working example:

Code:

#include <stdio.h>
int main(void)
{
	int i;
	
	char *source[] = {"abcdefgh", "ijklmnop"};
	char target[100];
	
	for (i = 0; i < 4; i++)
		target[i] = source[0][i];
	target[i] = '\0';
	
	printf("source[0]: %s\n", source[0]);
	printf("target: %s", target);
	
	return (0);
}