strcpy() function

strcpy() function is not working in MSVC++ 6

Heres what I have

#include <stdio.h>
main()
{
char varname[10];
strcpy(varname, string);
}

this gives me invalid identifier or something to that effect

do you have to do anything special with #include for MSVC++ 6 to recognize strcpy()

BTW I got this code from a book that I am learning from, however, it doesnt include visual c++ compiler stuff

any help appreciated

you might need #include <string.h>

also you need to declare the variable 'string' if you haven't already, char sintrg[ 10 ] = "thestring";

you have to give the array a value? I mean you cant simply define it first?

also i forgot to mention, im getting "strcpy invalid identifier"

Hi
As JRoosh says you will have to implement the library file for strings- which is <string.h>- this library contains various functions which can manipulate char strings- because you have omitted this your compiler recognises strcpy as just another variable. What you are trying to acheive is to copy the second argument in the function to the first argument- You have not declared the second variable string-
In your example code above you neither define the string or declare it as a variable. To copy the second string to the first you must give it a value as described below.
You will have to declare variable string and then either intialize it with whatever or have user input a string..as follows

Code:

/*FIRST ROUTINE*/
#include <stdio.h>
#include <string.h>

int main (void)
{
  char varname[10], string[]="Hello You";

  strcpy(varname, string);
  printf("%s", varname);
  /*this prints Hello You to display*/
}

/*2ND ROUTINE*/
#include <stdio.h>
#include <string.h>

int main (void)
{
  char varname[10], string[10];

  printf("\nEnter a string up to nine characters");
  gets(string);
  strcpy(varname, string);
  printf("\n %s", varname);
  /*this prints whatever user enters to the display*/
}

Cool, that pretty much clears it up thanks =)