Thread: I need help with my code [linked list]

Hello everyone,
this program is supposed to be quite simple. I tried to debug it for some time but couldn't realize what seems to be the problem. I'll be greatful for your help!

The functioned is meant to get an array and its size, and returns the address of a linked list only with the elements that appear once. example:
for this array:

57

9

88

74

57

88

74

57

6

57

the output will be:

---->6---->9

the code:

Code:

#include <stdio.h>
#include <stdlib.h>
#define N 40
typedef struct NODE node;
typedef struct NODE{
    int data;
    node* next;
};
node* list(int ar[N], int size);
void main(){
    int arr[] = { 57, 6, 57, 74, 88, 57, 74, 88, 9, 57 };
    node* new_list = list(arr[10], 10);
    node* tempi = new_list;
    while (tempi->next != NULL){
        printf("%d ->", tempi->data);
    }
    if (tempi->next == NULL) printf("%d", tempi->data);
}

node* list(int ar[N], int size){
    int i;
    node*head = (node*)malloc(sizeof(node));
    head->data = ar[0];
    head->next = NULL;

    for (i = 1; i < size; i++){
        node*temp = head;
        while((temp->data != ar[i]) && (temp->next != NULL)){
            temp = temp->next;
        }    
        if ((temp->next == NULL) && (temp->data != ar[i])){
        temp->next = (node*)malloc(sizeof(node));
        temp = temp->next;
        temp->data = ar[i];
        temp->next = NULL;
        }
    }
    
    return head;
    
}

about your second change - if I remove the number inside the brackets it says "expected an expression".

didn't notice the third one... thanks
it still encounters something endless and won't output anything though :/

It's working!
It didn't output the result it prints once all the numbers, rather the numbers that appears once.. but that's something I need solve

Thank you all very much!!