pointer to structure

**Satya** · 05-17-2015

Hi,
i am confused while writing this program

Code:

#include<stdio.h>
typedef  struct
{
    int (*p)[3];
}can1;
void function1(can1 *ptr );

int main()
{
int array[2][3]=
{
{1,2,3},
{4,5,6},
};
can1 cand={&array};
function1(&cand);
return 0;
}
void function1(can1 *ptr )
{
 printf("%d\n",(*ptr->p[1])[0]);
}

My explanation is something like this *(ptr->p[1]) is a pointer pointing to element 4 and *(ptr->p[1])[0] is the value at that address. But the compiler shows error. what is my mistake.

Thanks in advance,

**laserlight** · 05-17-2015

Recall that the operator -> already implicitly dereferences the left operand. Therefore, ptr->p is already the member pointer that points to an array of 3 ints, hence ptr->p[1][0] is an int.

**Satya** · 05-17-2015

I am getting the following warnings
warning: initialization from incompatible pointer type
warning: (near initialization for 'cand.p') in the line

Code:

can1 cand={&array};

What is the mistake? i am getting the proper output

**laserlight** · 05-17-2015

Think: what is the type of the variable named array? When this variable is converted to a pointer to its first element, what is the type of the resulting pointer? If you take its address, what is the type of the result?

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