Thread: Conversion of dec to hex

It appears that if "a" is not zero initially, you have an infinite loop. The value of "a" controls the "while()" loop, but is never updated within that loop.

I'd suggest you post the complete code (or at least a complete compilable example that illustrates the problem).

Also, you should use more descriptive variable names so it's easier (for us and you) to read your code.

I've handled the trouble in the bold code now it works perfectly.

Code:

#include<stdio.h>
#include"L5P21.h"     //that's my header

void conversion(unsigned int a,char c[])
{
   unsigned int i=1,d,remainder,m,j;
   while(a!=0)
   {
         remainder=a%16;
         c[i]=remainder;
         m=10;
         for(d=0;d<5;d++)
         {
             if(c[i]==m)
                {
                       c[i]='A'+d;
                 }
             m++;
          }
          i++;
}
printf("0X");
for(j=i-1;j>0;j--)
{
    if(isalpha(c[j]))
    {printf("%c",c[j]);}
    else
       printf("%d",c[j]);
}
}

[/QUOTE]

Originally Posted by vart

are you forbidden to use %x format for printing numbers?
I cannot see a logic in the exercise that prohibits %x but allows %d

The logic behind the assignment could be that it is simply a learning exercise, intended to give the student practice and experience.