Thread: question about void pointer ,stack ,ellipsis

I have an assumption and I don't know is this true or not:
If i use int arr[5];

Code:

arr[0]="hello";

the "hello"will store some where in the memory and the adress ofthat will store in the arr[0].
and I think when i have a function like this

Code:

void my_func(const char *string,...)

and I pass a string(array)to that function then it will store it some where in the memmory and the address of that will store in the stack but when I pass an integer type like 'j' to a function like

Code:

void test(char s){}

the j will store in the in stack directly not the address of it. is my assumption true?
now I want to call that function

Code:

my_func("hi how",45,'c');

and I want to point the next argument so I do it like this:

Code:

void my_func(constchar*string,...)
{
void*argptr = format;
    argptr =((int*)argptr +1);
}

but argptr points to the where "hi how" stored not to the stack (as my assumtion and I don't know if it's true or not)
how can I do that?

Check out this link.

Originally Posted by bki123

I don't want to (i'm not allowed) to use such macros.

If you don't use the standard methods of handling a variable number of arguments, you will have to rely on implementation-defined and/or platform-specific behavior.

One possibility might be to take the address of the first parameter, rather than the parameter itself, and add the size of the parameter to get the next one. Not all parameters are going to be the same size, so you'll have to know the type you want to extract from the list, and C won't tell you at run time what type the parameters are. In your case, you should probably use your first parameter, like a printf format string, to describe the remaining parameters.

Err... why are you not allowed to use such standard macros for such a standard solution?