Hi
Code:struct StudentData{ char name[30]; struct{ int midtermExam; int finalExam; int absenteeism; }Information; };
I have writed a function returning void value. I want to show in the screen.
Code:void showStudentStatus(struct StudentData *Students) { int i; struct StudentData *tempPointer; for(i=0;i<SIZE;i++) { tempPointer=Students; printf("%s",Students.Information->finalExam); // ERROR ISNT IT ? }
Please hep me?
Firstly, the printf()format needs to match whatever it is printing. %s is for strings. The finalExam member of the nested struct (Information) is an int, not a string, so needs to be printed using %d.
Second, assuming Students is of type "struct StudentData *" (as it is according to specification of your function arguments) AND that it points to a valid object, valid ways of accessing the finalExam member include
The "->" reflects the fact that Students is a pointer to a struct, Information is a member of that struct. The "." refers to the fact that "Students->Information" is a struct, not a pointer to a struct.Code:Students->Information.finalExam;
Alternatively, If Students points to the first element of an array, and i is a valid index in that array, then one way to access the same member (for the i'th element in the array) is
In this case, no need for "->" since Students[i] accesses the struct, and is not a pointer.Code:Students[i].Information.finalExam;
You code doesn't need the variable tempPointer at all. Particularly since, other than assigning a value to it, your code never uses it.
grumpy
Thank you so much. I understood very well. Thanks a lot... You're wonderful guy.
