Thread: how to create array who point to some value?

Originally Posted by gevni

I have to create dynamic array, where each element of it points to some value.

Dynamically create an array of pointers to something (for example, a struct type).

Originally Posted by gevni

I know how to create dynamic array

Code:

array_record * record_1 = (array_record*)malloc( (group!/(2!(group!-2)!)) *sizeof(array_record));

By this example, you have demonstrated you don't know how to dynamically allocate memory. The syntax (e.g. the presence of exclamation marks) is invalid, and will not compile.

Also, it is not necessary in C to do a type conversion on the value returned by malloc().

Originally Posted by gevni

But i don't know how i create this case. for example what i want if array elements are:

Code:

index  value   value
0       01  -> 345
1       02 -> 457
2       03 -> 689
3       21 -> 634

so if i have value somewhere 01 match with 01 in this array it display 345. Can you please help me how i can implement it?

Define a struct type to hold the required values in association with each other. Dynamically allocate an array of that struct type, and then populate it.