Thread: İf- else problem (new in c)

Code:

#include <stdio.h>

int  main()


{
      
char  a;
long  b;
 
 printf("Name and password :");
 scanf ("%c %lb", &a, &b);
 
  if((a=='onur') && (b=="160897456")) 
              
              {
              printf("hello sir");
              }
              else
              {
              printf("nice try");
              }
       getchar();  
       getchar();
       getchar();
       getchar();
      
      
}

erors :
multi-character character constant
comparison is always false due to limited range of data type
ISO C++ forbids comparison between pointer and integer

What am ı doing wrong? And whats is your suggestions ? I think i dont understand properly . Which subjects do ı need to study ?

Code:

(a=='onur')

A single character is enclosed within single quotes (e.g. 'a').
A string is enclosed within double quotes (e.g. "string").

A string is a character array terminated with a null character ('\0').

Strings: C Strings - Cprogramming.com

Note:
- 'onur' should be "onur"
- your variable 'a' should be an array
- you can't compare strings in C with == ... you need to use a function like "strcmp()"

Code:

(b=="160897456")

An integer is not enclosed within double quotes; that is only for strings. You want to do:

(b==160897456)

Also:

Code:

scanf ("%c %lb", &a, &b);

"%lb" should be "%ld".

Code:

getchar();  
getchar();
getchar();
getchar();

Not a good approach. Some more reading:

FAQ > Stop my Windows Console from disappearing everytime I run my program? - Cprogramming.com
FAQ > How do I avoid a "dangling" newline when reading single character user input? - Cprogramming.com

Originally Posted by Onur Berk Töre

Which subjects do ı need to study ?

What C books have you read?

Originally Posted by FloridaJo

What C books have you read?

I dont think you know that because book is Turkish, "A to Z C" /Kaan Aslan