Thread: characters array

Hello everybody,so my question is i want to print characters,no string just an array of characters,i do this but it s not working,maybe i have to put the '\0' at the end?

Code:

int main()
{
    int i;
    char ch[5];

for(i = 0; i < 5; i++)
{
    scanf("%c",&ch[i]);
}

for(i = 0; i < 5; i++)
{
   printf("%c\n",ch[i]);
}
    
    
    
}

How is it "not working"? Seems okay to me:

Code:

hello
h
e
l
l
o

The way you're doing it, you don't need the '\0' at the end. That marks the end of a string. Technically, you're working with single characters at a time.

oh, ok, now i get it, i was accidentally typing in a character and then pressing enter, so it was also recognizing ENTER as a character. I should have typed ALL 5 characters together and then press ENTER.,thanks,i have one more question

Code:

int main(void)
 {
 int count;
  
 printf("Enter a  line of text:\n");
 printf("EOF to  stop.\n");
  
 count = getchar();
  
 while(count !=  EOF)
 {
      putchar(count);
      count = getchar();
 }
      return 0;
 }

1)how can i enter characters instead of integers when the variable is INT?

2)why does it insert GETCHAR() outside the while and then go back into the while?

3)i thought the EOF[end of file] is the last character of the string or '\0', what does CTRL -D have to do with it?

oh, ok, now i get it, i was accidentally typing in a character and then pressing enter, so it was also recognizing ENTER as a character.

Well done on coming to that conclusion yourself! If you're interested in more reading about that, there's a link in the FAQ: FAQ > How do I avoid a "dangling" newline when reading single character user input? - Cprogramming.com

1)how can i enter characters instead of integers when the variable is INT?

Characters can typically be thought of as small integers. They both basically represent numbers - it's just that many systems use the value of a character to determine which "character symbol" to be printed. Regardless if you're storing the result of "getchar()" into an int or a char, it is still recognized as a character. For instance, if you enter the number one, the result is the character '1' and not the number 1 being stored.

A common implementation is ASCII - if you look at the chart, you'll see that the character '1' actually has a value of 49 in that encoding.

As to why a function called "getchar()", that gets a character, returns a data type "int" (and not "char")? It's because a char is not guaranteed to be large enough to hold the value of EOF. More on that here: FAQ > Definition of EOF and how to use it effectively - Cprogramming.com

2)why does it insert GETCHAR() outside the while and then go back into the while?

It doesn't. The program is executed sequentially, so the first "getchar()" is called before the loop, and all subsequent "getchar()" calls occur within the loop.

3)i thought the EOF[end of file] is the last character of the string or '\0', what does CTRL -D have to do with it?

Cntl-D (on some systems) triggers EOF.

>> i thought the EOF[end of file] is the last character of the string or '\0'

Read the link on EOF I posted above - it explains what EOF is and is not.

Thank you for your valuable help, I appreciate it,,have a nice day

The code of yours works great but it could perhaps be written a bit cleaner. Consider the re-written code.

Code:

int main(void)
 {
 int count;


 printf("Enter a  line of text:\n");
 printf("EOF to  stop.\n");


 while( ( count = getchar() ) != EOF )
 {
      putchar(count);
 }
      return 0;
 }

Its the exact same thing only yours except I put the input and comparison for EOF inside the while condition.