Cycling through memory to print string with and without function problem

[watdapho]

Hello there !

Noobie here, just joined the community ^_^

Anyways, I have a problem where I'm trying to cycle through memory via pointers to print a string. Here is my code:

#include <stdio.h>

int main(void){

    char word[]="hello there";

    int *pword = word;

    for(;*pword!='\0';pword++){
           printf("%c",*pword);
    
     }

    return 0;
}

When compiled, the returning string is "hoe".

Funny thing is, whilst experimenting and trying to find alternate ways to get this done right, using a function to print seems to get the trick done. Here's my code using a function.

#include <stdio.h>

int main(void){

    char word[]="hello there";

    print(word);

    return 0;
}

void print(char *word){

    for(;*word!='\0';word++){
           printf("%c",*word);
}

}

This seems to effectively portray what I want

How do I print a string using the same method for(;*pointer!='\0';pointer++) without a function?

Kind regards

[jimblumberg]

Look closely at the following snippet. Do you notice any differences between the type of the variables?

    char word[]="hello there";
 
    int *pword = word;

Jim

[watdapho]

Look closely at the following snippet. Do you notice any differences between the type of the variables?

    char word[]="hello there";
 
    int *pword = word;

Jim

OH SHOOT! I am supposed to put char! THANK YOU