Thread: Help in the code

Hey Guys,

I got the following code by doing Google search. I have made some changes in this code to suit my self. It's basically for finding Lychrel numbers. The code is:

Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
 
long long reverse(long long i)
{
    int rem;
    long long sum = 0;
 
    while(i > 0)
    {
        rem = i % 10;
        sum = (sum * 10) + rem;
        i /= 10;
    }
    return sum;
}
 
int main()
{
    int i, count, ans = 0;
    long long next;
 
    for(i = 10; i < 10000; i++)
    {
        count = 0;
        next = reverse(i) + i;
        while(count < 50)
        {
            if(reverse(next) == next)
            {
                break;
            }
            else
            {
                next = reverse(next) + next;
                count++;
                if(count == 50)
                {
                    ans++;
                }    
            }
        }
    }
    printf("Answer is %d\n",ans);
}

I want to write the code without using BREAK or GOTO keywords, but I'm not able to figure out. If possible please help and give your inputs.

Thanks in advance.

Replace the break with a boolean flag

Can you please be more specific. I didn't get what you said.
Thanks

Originally Posted by abhinav3

Can you please be more specific. I didn't get what you said.
Thanks

Instead of breaking from the loop, add another condition to the loop.

I don't think I should get more specific than that because this really smells like homework (otherwise why avoid using break?)

Yes, it is homework. The system that I work on doesn't support use of BREAK and GOTO statements.
So if you could help me, it would me great.
Thanks