Thread: C-another Pointer program.

Originally Posted by 5360

I am starting to understand pointer but still confused.

I note that you do not directly use any pointers in your program.

Originally Posted by 5360

Does sum equal to 13?

Use a debugger to find out. If one is not available to you, then print the value of sum at the point where you want to know what it is equal to.

Originally Posted by 5360

If so, what is a,b,c and where to obtain the variables for a,b,c: a+b+c=13?

It looks like your assignment is designed for confusion. I suggest that you consider this program, which is exactly the same as the program you posted except for variable names:

Code:

#include <stdio.h>

int f(int x, int y, int z);


int main() {
    int a=2, b=3, c=5;
    printf("a=%d b=%d c=%d\n",a,b,c);

    a = f(b, a, b+c);
    printf("a=%d b=%d c=%d\n",a,b,c);



    system("pause");
    return 0;
}


int f(int x, int y, int z) {
    int sum;
    sum = z + y + x;
    if(sum > z * x)
        return z*x;
    if(sum <= y * x)
        return y * x;

    return z * y;
}

Originally Posted by 5360

Why are there two returns assuming one of the "if" statement is true?

The first of the two for which the if statement's condition evaluates to true will be used.

Originally Posted by 5360

Lastly, what does

Code:

a = f(b, a, b+c);

implies?

That is just a function call.

Originally Posted by 5360

One last question, how do I find the variables for x,y, and z that will equal to sum?

What do you mean?

Consider a simpler example:

Code:

#include <stdio.h>

void print_number(int n)
{
    printf("%d\n");
}

int main(void)
{
    print_number(10 + 20);
    return 0;
}

So, the value of the formal parameter n is the value of the actual argument passed when calling print_number, i.e., 10 + 20, hence the value of n is 30.