I have a code in which I am passing string "5368709120" to function strtoull() and it should had returned me number 5368709120 but instead it returns me 1073741824 which is incorrect.
What may be the possible cause of this and how to rectify it?
Code:typedef unsigned long long ULL_Type; char *quotaStr = "5368709120"; ULL_Type quota; quota = strtoull(quotaStr, NULL, 10);
how do you print this number?
All problems in computer science can be solved by another level of indirection,
except for the problem of too many layers of indirection.
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C function "strtoull" failing - The UNIX and Linux Forums
Please do not post the same question everywhere. This requires that you read about one paragraph of documentation on printf format strings. You can't print the correct value.
Works for me....
Perhaps it's the brain damage you're using to try and print the result.Code:$ cat foo.c #include <stdio.h> #include <stdlib.h> int main() { typedef unsigned long long ULL_Type; char *numStr = "5368709120"; ULL_Type num; num = strtoull(numStr, NULL, 10); printf("%s converted to numeric=%llu\n", numStr, num); return 0; } $ gcc -Wall foo.c $ ./a.out 5368709120 converted to numeric=5368709120
Perhaps you're not using %llu as the printf format.
Perhaps you're using code::blocks or Orwell dev-C++ on windows, in which case you need to use the platform specific formats for the 64-bit types.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
