Declaring an array within a function's argument

[LiteHacker]

Hello,

I have a function

int exec_program(char * arguments[])
{
...
}

I can call it like this without a problem:

char * uselessvariable[] = {"/bin/echo", "Testing", NULL};
exec_program(uselessvariable);

However I get an error if I try to compile it like this:

exec_program({"/bin/echo", "Testing", NULL});

Do you know how, in c, I can put this array inside of the argument in one line without having to name a new variable name?

[smokeyangel]

A braced list of pointers like that could be any number of things, e.g. a struct of three void pointers. So you need to tell the compiler what it is with a cast, like so:

exec_program((char * []){"/bin/echo", "Testing", NULL});

[LiteHacker]

A braced list of pointers like that could be any number of things, e.g. a struct of three void pointers. So you need to tell the compiler what it is with a cast, like so:

exec_program((char * []){"/bin/echo", "Testing", NULL});

Thank you.