Thread: Having issues "hardcoding" an integer

Hello everyone! I am just starting to play around with C programming, not C++, not C#, but just C. I'm trying to write a program that declares an integer called num and "hardcodes" the value to be 1000. Then I need to use a printf() statement that displays "1000 is the value of the variable num". I have some of the programming done so far but when I use the %d format specifier instead of 1000 being displayed I get a 0. Can someone please help me? I can't figure out what I've done wrong/not done.

Don't define a number twice. You've already declared an int and I think C, by default, initializes it to 0. Or is that just C++? I knew this would happen if I started learning other languages.

Originally Posted by MutantJohn

Don't define a number twice. You've already declared an int and I think C, by default, initializes it to 0. Or is that just C++? I knew this would happen if I started learning other languages.

Global and static variables are initialized to 0 or NULL, by default. Automatic variables are not.

To clarify and expand on what Adak said:
In the OP's case, num is an automatic storage duration variable. Whether it is initialized is hard to say, the code they posted wont compile, so no way to know what the code they ran actually was.

Variables with static storage duration (global variables and static local variables) are implicitly (by default) initialized to 0/NULL only if they are not explicitly initialized.

Variables with automatic storage duration (non-static local variables) are not implicitly initialized to anything (i.e. they contain "garbage" values and shouldn't be used without first giving them a reasonable value). They may, however, be explicitly initialized.

There's more to it than that, for full details, see C99/C11 6.7.8 Initialization and C99/C11 6.2.4 Storage duration of objects

%d is a formatter for integer values. When you use %d in a printf statement always specify the variable after string quotes followed by a comma with an integer. In your case you are don't doing that. Also, when you define a variable, you don't need to define it again to assign something to it. Furthermore, you don't need to open new quotes to put \n. And whenever you finish with the main function, always return 0.

Code:

//This is wrong
int x;
int x = 100;

//This is correct
int y;
y = 100;

//This is also correct
int z = 100;

Try this code, its a fixed version of yours.

Code:

#include <stdio.h>

int main()
{
    int num = 1000;
    printf("%d is the value of the variable num\n", num);
    return 0;
}