K&R array program learning

This is a discussion on K&R array program learning within the C Programming forums, part of the General Programming Boards category; hello experts i am learning K&R array program i have a lot of doubts please help me How the output ...

  1. #1
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    K&R array program learning

    hello experts i am learning K&R array program i have a lot of doubts please help me

    How the output shows as digits = 2 1 1 1 1 1 1 1 1 1 ?

    Code:
    #include<stdio.h>
    int main()
    {
    	int c,i,nwhite,nother;
        int ndigit[10];
    
        nwhite = nother = 0;
        for(i = 0; i < 10; ++i)
        	ndigit[i] = 01
        	;
    
        while((c = getchar()) != EOF)
        	 if(c <= '0' && c <= '9')
        		 ++ndigit[c- '0'];
        	 else if (c == "" || c == '\n' || c == '\t')
           		 ++nwhite;
        	 else
        		 ++nother;
            printf("digits =");
            for(i = 0; i < 10; i++)
            	printf(" %d ", ndigit[i]);
                printf(",white space = %d, other = %d \n", nwhite ,nother);
    
    }
    In put
    1
    2
    3
    4
    5
    6
    7
    8
    9
    0
    l
    a
    s
    d
    f

    Output
    digits = 2 1 1 1 1 1 1 1 1 1 ,white space = 0, other = 14


    thanks

  2. #2
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    Join Date
    Apr 2013
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    1,314
    Indentation fixed. Actual fixes noted with // comments. The main issue was c <= '0' when it needed to be c >= '0'.

    The program is generating a histogram.

    Code:
    #include<stdio.h>
    int main()
    {
        int c,i,nwhite,nother;
        int ndigit[10];
    
        nwhite = nother = 0;
        for(i = 0; i < 10; ++i)
            ndigit[i] = 0;                                  // 0
    
        while((c = getchar()) != EOF)
             if(c >= '0' && c <= '9')                       // >= 
                 ++ndigit[c- '0'];
             else if (c == ' ' || c == '\n' || c == '\t')   // ' '
                 ++nwhite;
             else
                 ++nother;
        printf("digits =");
        for(i = 0; i < 10; i++)                             
        // spaces on the next two lines
            printf(" %d", ndigit[i]);
        printf(", white space = %d, other = %d\n", nwhite ,nother);
        return(0);                                          // return
    }
    Input, if one line:

    Code:
    1234567890|asdf
    Last edited by rcgldr; 08-24-2013 at 05:51 PM.

  3. #3
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    Jun 2005
    Posts
    6,452
    You might also want to look up functions in the standard header <ctype.h>. There are facilities there like isdigit() to test if a character is a digit, isspace() to test if a character is whitespace, isalpha() to test for alphabetic characters, and more.

    Note that those standard functions also work with internationalisation (for example, the notion of what is an alphabetic character varies with natural language). Also, there are more whitespace characters than just the three you are testing for.
    Right 98% of the time, and don't care about the other 3%.

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