Thread: increment operator

Code:

#include<stdio.h>
void main()
{
    int i=5;
    printf("%d\n",i++ + ++i);
}
this code prints the value as 12 because for 1st i will be taken as 5 and then it is incremented to 6 which is again incremented to have value 7 for 2nd i......but if we change the printf statement to printf("%d\n",i++ + i++); it gives 10 as output and also if printf("%d\n",i++ + i++ + ++i); gives 16 as output....
Please help me thru this ??

This is undefined behavior and should be avoided

First things first: We use to write

Code:

int main(void)
{
      ....
      return 0;
}

Also, try to keep your text outside the code tags

Increment operators can lead to undefined behavior if they are not used as they ought to be.
I have gathered examples from around here and you can take a look at this link.

I think what you have there is an example of undefined behavior.

Over 18 months ago, you asked basically the same question.
calculation

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