if you have something like this how can you print the string in main??
Code:/#include <stdio.h> #include <stdlib.h> void myf(char *p) { p="balls"; } int main() { int i=0,j; char ch[10]; myf(ch); for(i=0;i<10;i++) printf("%c",ch[i]); printf("\n"); system("PAUSE"); return 0; }
p is just a copy of ch in main. it's value is lost after return from myf().
try
to make the function safe you should pass the size of the buffer as well and use strncpy().Code:void myf(char *p) { strcpy( p, "balls" ); }
Kurt
Last edited by ZuK; 05-23-2013 at 11:35 AM.
since you are passing the address of a char array, you need to copy the string into it in myf. p is local to myf, so changing it in your function doesn't affect any value in main. but p is pointing at the char array 'ch' so you can copy data to where it is pointing.
Code:void myf(char *p) { strcpy(p,"balls"); }
however you usually would want to pass in the length of the destination array and use strncpy to avoid accidental overruns.
