Hi!!!Here is a function,which deletes the spaces of a string...
char *removespaces(char *s1)
{
Could you explain me why I have to initialize the pointer *s2 with the first element of the array s1...???If I don't initialize the pointer,or initialize it with something else,I get a segmentation fault...Code:char *s2=s1; int i,j=0; for (i = 0; i<strlen(s1); i++){ if (s1[i]!=' ') { s2[j]=s1[i]; }else { j--; } j++; } s2[j]=0; return s2; }
Last edited by evinda; 04-27-2013 at 12:11 PM.
You haven't allocated any memory for s2 to use, so your s2[j] is a real problem. I suggest you click on the C tutorial link at the top of the web site, and review the part that deals with memory allocation, especially malloc() .
You don't HAVE to use that pointer, btw. It's OK to use another static array or just j for this.
I don't know why s2 is even used, since it's set to the same as s1.
I havent get taught malloc() yet...Isn't it right to use pointers???
I have to write a function,that removes the spaces of a string,and to return the result,so I thought that I should use an other pointer...
A pointer needs some memory to point to, that has been set aside. You don't have that.Originally Posted by evinda
I havent get taught malloc() yet...Isn't it right to use pointers???
I pointer is like the tip of a compass needle - it points to something - maybe a bucket - that will hold water. The compass needle itself, can not hold water - that's what the bucket's for.
No you shouldn't be using a pointer, yet. You should be using the variables i and j. You are almost there!
Take half a dozen pennies and put them in a line, on the table. Put some spaces between some of the pennies.
Now slowly adjust the pennies going from one end to the other, so the spaces are removed.
How did you do that? Describe it in step by step simple terms that the computer can work with. Repeat that a few times, and you'll see an insight into the logic you need for this function.
Yes, I know exactly what your assignment is. It's very common.
Last edited by Adak; 04-27-2013 at 01:01 PM.
But....the exercise requires the use of pointers....
Instead of using the indices i and j, you could use two pointers. They both start at the address of s1, and then diverge from one another, as spaces are found and removed, from s1.But....the exercise requires the use of pointers....
There is no good reason to return a char pointer, since s1 is already being returned modified, with no more spaces.
What else would you return, besides s1?
I don't know...
You have s1, but the size of s1's string will have changed. I would return that new length of the string s1.I don't know...
But that would be an int, not a char pointer.
You could return a char pointer with the address of the last char in the string. Then subtract s1 from it, and use that as the new length of the s1 string.
That would make sense. Not my preference, but sense.
Last edited by Adak; 04-27-2013 at 11:47 PM.
Returning the original pointer allows you to include your function as part of a statement, for example:
will print "thisisatest".Code:printf("%s\n", removespaces("this is a test"));
In your original code example, s2 isn't needed and every occurrence of s2 in your program could be replaced with s1 and it would still work.
As Adak mentioned, if you were supposed to just use pointers without indexing, then you would need s2, and you'd also need another pointer to preserve the original input pointer. Here's a partial example of this method, but missing the part you're probably supposed to figure out as part of your assignment:
Code:char *removespaces(char *s0) { char *s1 = s0; char *s2 = s0; while(*s1){ if(' ' != *s1) /* you fill in this part */ } *s2++ = 0; return s0; }
