Thread: please i need help for my assignment

Write a for loop statement to print the numbers from 1 to 10 in reverse order separated by star :

10*9*8*7*6*5*4*3*2*1


i try to do it but it show me like this :


10*9*8*7*6*5*4*3*2*1*

how do i write to show me like the first one ?

Show your current code and maybe someone can point you in the right direction.

Jim

Code:

int main(int argc, char *argv[])
{
    
    for (int start = 10; start >= 1 ; start=start-1){




    printf("%d*",start);
   }


    return 0;
}

here is my code

you mean should i do another for loop ?

No, just don't print the first character in your present loop. Print it after the loop without the asterisk.

Jim

Code:

 int main(int argc, char *argv[]){
	
    for (int start = 10; start >= 2 ; start=start-1){


printf("%d*",start);
    
   } for(int x =1; x>= 1; x--) { printf("%d",x); }


    return 0;
}

is that right ?

No, I said you don't need two loops. Why do you have tow loops?

But you will need to define start before your loop.

Code:

int main(int argc, char *argv[]){
    int start;
    for (start = 10; start >= 2 ; start=start-1){

Jim

i am really sorry but my Engilsh is weak . but i don't understand
how I print the last 1 outside the loop

Code:

Code:

int main(int argc, char *argv[])
{
	int start; 


    for (int start = 10; start >= 2 ; start=start-1) { printf("%d*",start);  } 




		
    return 0;
}

Originally Posted by abo5aleil

i am really sorry but my Engilsh is weak . but i don't understand
how I print the last 1 outside the loop

Code:

Code:

int main(int argc, char *argv[])
{
	int start; 


    for (int start = 10; start >= 2 ; start=start-1) { printf("%d*",start);  } 




		
    return 0;
}

Don't include the last number in your loop.
Print the final value after the loop, so it's not subject to receive an *

why dont u use "if" statement?
so when the number gets to 1, the * will not print.