Array function not returning correct valuse

[phillyflyers]

Hi Guys, I have been trying to make a function that compares all the values of the array and if they are all equal will return a value to print true. The problem I am having is that regardless of what values I enter the function is always returning true. I couldn't really figure out a way to tell the program o check all the values in one command instead I put them each, If you guys see any thing wrong or any advice it would be greatly appreciated. Thanks again.

 #include<stdio.h>

#include<stdlib.h>


　

　

　

int compare(int arrayA[], int arrayB[]);


int main()

{


int i = 0;

int k = 0;

int arrayA [10];

int arrayB [10];

int T = 0;


for(i = 0; i < 10; i++)

{

    scanf("%d",&arrayA[i]);


}


printf("\n\n");


for(k = 0; k < 10; k++)

{

    scanf("%d",&arrayB[k]);

}


    T = compare(arrayA, arrayB);


if(T = 1)

    {

    

        printf("\n True");

    }


else

    {

    

        printf("\n False");

    }


　

　

　

　

}

int compare(intarrayA[], intarrayB[])

{


int T = 0;

    


if(arrayA[0] == arrayB[0] && arrayA[1] == arrayB[1] && arrayA[2] == arrayB[2] && arrayA[3] == arrayB[3] && arrayA[4] == arrayB[4] && arrayA[5] == arrayB[5] && arrayA[6] == arrayB[6] && arrayA[7] == arrayB[7] && arrayA[8] == arrayB[8] && arrayA[9] == arrayB[9])

{

    

    T = 1;

    


return(T);

}


else

{

    T = 0;

return(T);

}


　

}  

[laserlight]

For starters, you need to indent your code properly. Your problem is likely due to this line:

if(T = 1)

Recall the difference between = and ==.

By the way, instead of naming your function "compare", a name like "is_equal", "all_equal", "compare_equal" or even just "equal" would likely be more descriptive.

[phillyflyers]

Wow, lol thank you so much after staring at the code you just don't see simple mistakes especially since I'm new to this lol. I want to really thank you for your help and I will try to indent and give better descriptive names. Thanks again for your help it is greatly appreciated.