I have a function which is declared as the following
When I try to call it as followsCode:void errorParser(int error,char* dir)
I get the following error:Code:errorParser(errno,(const char*)getenv("HOME"));
passing arg 2 of 'errorParser' discards qualifier from pointer target type?
What does that mean? And should I be worried about it?????
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> What does that mean?
Means what it says
The parameter in the function prototype is
char *
The parameter you are passing is
const char *
const is a qualifier, and it's being discarded by the (implicit) cast to make a 'const char *' into a 'char *'
> And should I be worried about it?
Perhaps
Does errorParser modify the dir parameter?
If it does, then you're sunk - who knows what could happen
If it doesn't, the best fix is to declare
void errorParser(int error, const char* dir)
Then it wont matter whether you pass a const char* or a char* to it.
