append to file with write()

Hi!

I have an array with two digits:

Code:

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int digits[2];
dprintf(digits, "%d", number);

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Now I want to append those digits to my textfile:

Code:

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write(writeToFile, digits, sizeof(digits));

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But how come the result looks like this in the textfile, what was appended was this:

Quote:

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^A^D^@^@^B^@^@^@

---

Would someone know the reason for this?

thank you!

write() writes bytes to the file, but you probably want to write text.

Look at fprintf().

Bye, Andreas

dprintf() probably adds a terminating null. If you have only two characters, you will corrupt memory. This can cause all sorts of strange things to happen.
But I suspect that there's also a problem with the way you opened the file. Since you didn't post that section of your code, it's impossible to diagnose it.

ok so I dig in to fprintf.

I make a FILE like this:

Code:

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FILE *fp = fopen(argv[1], "a+"); //read and append

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And append the file with this:

Code:

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fprintf(fp, "\n\n%d", number);

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the variable number is an int and contains 3.

This time nothing hapens, should this not be all needed to append this textfile?

Please post a complete (non)working program not just random lines.

Bye, Andreas

ok I pasted all my random lines togeather here:



bash$ ./a.out file.txt

NEVERMIND!!! I found out that its because I did not use fclose(fp)!! :) victory! :D thank you all very much for yout time