Thread: Calculating the next day

Hi there,

Thanks again for those that helped with my Easter Sunday program. I was able to complete it.

Currently I am working on a program where you enter in a date 14 03 2013 (Day, Month, Year) and you get the next day. I seem to be coming stuck with months with less than 31 days, and the whole leap year thing.

Here is my code so far.

Code:

#include <stdio.h>

int day, month, year, next_day, next_month, next_year, calculation;

int main() {
    printf("Enter a date in the form day/month/year: ");
    scanf("%d %d %d", &day, &month, &year);
    calculation = month - 1;
    if (month == 2) {
        if (year % 100 == 0) {
            if (year % 400 == 0) {
                calculation = 29;
            } else if (year % 4 == 0) {
                calculation = 29;
            }
            next_day = next_day +1;
            next_month = month;
            next_year = year;
            if (next_day > calculation) {
                next_day = 1;
                next_month++;
            }
            if (next_month > 12) {
                next_month = 1;
                next_year++;
            }
            printf("The date of the next day is: %d %d %d", next_day, next_month, next_year);
        }
    }
}

Is there anything you can suggest to help me get my program working?

Okay.

I've started writing my code again this time piece by piece. Focusing now on days and months (April, June, September and November).

Code:

#include <stdio.h>

int day, month, year;
bool leapyear;

int main() {
    printf("Enter a date in the form day/month/year: ");
    scanf("%d/%d/%d", &day, &month, &year);
    day = day + 1;
    if ((month = 4) || (month = 6) || (month = 9) || (month = 11) && (day = 30)) {
        day = 1;
        month + 1;
    }
    printf("The date of the next day is: %d/%d/%d", day, month, year);
}

So helpful! Thanks!