Thread: C programming help Please!

Well, we can't see question 2.

So, is the requirement to step through the entire range of resistance for each step in voltage - or to step through both at the same time, given that each is basically 5 steps? This will affect whether you need nested loops or just one loop.

In the innermost loop you probably meant to have:

Code:

total = i/j;

Code:

#include<stdio.h>

Code:

main(){float i,j,total; for(i=0;i<=50;i=i+10){for(j=100;j<=1000;j=j+200){      total = i/j; printf("%.2f,total); }}  getch();}

Code:

#include<stdio.h>
main()
{
  float i,j,total; 
  for(i=0;i<=50;i=i+10)
  {
	  printf("\n\n");
  for(j=100;j<=1000;j=j+200)
  {
      total = i/j; 
      printf("%.2f",total); 
   }
}
  getch(); 
}

is this right format?

the output i get is this

0.000.000.000.000.00


0.100.030.020.010.01


0.200.070.040.030.02


0.300.100.060.040.03


0.400.130.080.060.04


0.500.170.100.070.06

No, you need to give your numbers a total width of field:

Code:

printf("%6.2f ",total);

Now the numbers won't be running together one column to the next. Adjust the six as needed, but keep the space after the f.

Originally Posted by Adak

No, you need to give your numbers a total width of field:

Code:

printf("%6.2f ",total);

Now the numbers won't be running together one column to the next. Adjust the six as needed, but keep the space after the f.

Thank you so much Mr.Adak. Now the programming is running. Thank You.

Code:

#include<stdio.h>
main()
{
  float i,j,total; 
  float a=0,b=10,c=20,d=30,e=40,f=50;
  printf("%12.2f ",a);
  printf("%6.2f ",b);
  printf("%6.2f ",c);
  printf("%6.2f ",d);
  printf("%6.2f  ",e);
  printf("%6.2f ",f);
  for(i=100;i<=1000;i=i+200)
  {
              printf("\n\n");
              printf("%6.2f" , i);
              for(j=0;j<=50;j=j+10)
      {
      total = j/i; 
      printf("%6.2f ",total); 
      }
  }
  getch(); 
}

Code:

#include<stdio.h>
#include<conio.h>
main()
{
int i,j;
clrscr();
for(i=5;i<16;i+=2)
{
for(j=3;j<7;j++)
{
printf("%d",i*j);
}
printf("\n");
}
getch();
}

Originally Posted by jorgedobson

Code:

#include<stdio.h>
#include<conio.h>
main()
{
int i,j;
clrscr();
for(i=5;i<16;i+=2)
{
for(j=3;j<7;j++)
{
printf("%d",i*j);
}
printf("\n");
}
getch();
}

Welcome to the forum, Jorge! Thanks for using code tags on your first post!!

May I make two important recommendations for your coding?

1) It's never just main(), it's always int main() with a return (normal run time evidenced by a zero), so return 0, at the end of your programs.

and

2) Indenting your code - where subservient lines of code are indented 2 to 5 spaces - is important. It makes the logic "pop" out as people read it/study it.

Originally Posted by Adak

Welcome to the forum, Jorge! Thanks for using code tags on your first post!!

May I make two important recommendations for your coding?

1) It's never just main(), it's always int main() with a return (normal run time evidenced by a zero), so return 0, at the end of your programs.

and

2) Indenting your code - where subservient lines of code are indented 2 to 5 spaces - is important. It makes the logic "pop" out as people read it/study it.

Dear return type doesn't meter we just follow output...