Get character from a word with number

This is a discussion on Get character from a word with number within the C Programming forums, part of the General Programming Boards category; Heyy guys, i'm new here, im trying to fix a problem but cant find a way to do it...its only ...

  1. #1
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    Get character from a word with number

    Heyy guys,
    i'm new here,
    im trying to fix a problem but cant find a way to do it...its only works with the first letter.

    so i have a txt file with information such as de3 dn5 dn7 dw9 ds1
    and im trying to figure out how to get the letters and then the number

    exemple:

    if de

    print this is de;
    and print the number that follow de


    thanks.

    i'll post the code that i have

    Code:
    #include <stdlib.h>
    
    int main ()
    {
        FILE * pFile;
        int c;
      
        pFile=fopen ("de3.txt","r");
        if (pFile==NULL) perror ("Error opening file");
        else
        {
    
        c = fgetc(pFile);
         while(c)
         {
             if(isdigit(c))
             {
                printf("the digit is %d", c);
             }
             if( c == 'd' && c == 'e')
                {
                    printf("its on east");
                }
                else
                if( c == 'd' && c == 'n')
                {
                    printf("its on north");
                 
                }
                }
    
        }
        fclose (pFile);
        return 0;
    }
    Attached Files Attached Files
    • File Type: c try.c (652 Bytes, 28 views)

  2. #2
    young grasshopper jwroblewski44's Avatar
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    You want to "get" the letters and then "get" the number, but where do you want to store them? Also you never change the value of 'C' in your while loop, so when will it ever end?

  3. #3
    young grasshopper jwroblewski44's Avatar
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    Also, nice job formatting your code on your first post! Welcome to the forum!

  4. #4
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    c will never end because its will always going to have to loop to check whether its de3 or else, and i was thinking about storing it to a pointer or array but i was confuse to whether i need different array for different word.

  5. #5
    young grasshopper jwroblewski44's Avatar
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    Quote Originally Posted by Tryhard View Post
    c will never end because its will always going to have to loop to check whether its de3 or else, and i was thinking about storing it to a pointer or array but i was confuse to whether i need different array for different word.
    I wasn't referring to 'C' ending, I was talking about your while loop. You never change the value of 'C', so if you input a non-zero value for your first iteration, your loop will run infinitely.

    I'm not quite sure what the purpose of the program you're trying to write is. Also I don't understand your question.

    http://www.wikihow.com/Ask-a-Question-Intelligently Please read through this link and then re-post your question.
    Last edited by jwroblewski44; 03-02-2013 at 08:34 PM.

  6. #6
    Registered User hk_mp5kpdw's Avatar
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    Code:
    if( c == 'd' && c == 'e')
    
    ...
    
    if( c == 'd' && c == 'n')
    A variable can only ever have a single value. The int variable c will never be both 'd' and 'e' (or both 'd' and 'n') at the same time. You will therefore never enter the blocks of code controlled by these statements.
    "Owners of dogs will have noticed that, if you provide them with food and water and shelter and affection, they will think you are god. Whereas owners of cats are compelled to realize that, if you provide them with food and water and shelter and affection, they draw the conclusion that they are gods."
    -Christopher Hitchens

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