Thread: I didn't understand how each word newline program

Code:

#include <stdio.h>


int main(void)
{
    int c;
    int inspace;
	
    inspace = 1;
    while ((c = getchar()) != EOF)
    {
        if (c == ' ' || c == '\t' || c == '\n')
        {
            if (inspace == 0)
            {
                inspace = 1;
                putchar('\n');
            }
/* else, don't print anything */
        }
        else
        {
            inspace = 0;
            putchar(c);
        }
    }
	
    return 0;
}

I tried this code w/o no "inspace" in it and code still worked but if I made more than one blanks between words it happened vertically double newlines etc.. so I just wanna know how this "inspace" makes newline w/o blank line for each word. Is that a flag ? if it is how compiler handle this please let me know I couldn't understand

Originally Posted by GReaper

Yes, it's a flag. If it's the first sequential space, tab or newline -> print a newline. If not, do nothing.

flag's initial value 1
then lets say result of "c == ' ' || c == '\t' || c == '\n'"
equals to 1
then dont we check the value of inspace if it is 0 and started with inspace was 1 thats where I got confused

Originally Posted by GReaper

But if the input is anything else, "inspace" is reset to zero. Practically, by initializing it to one, you ignore every space, tab and newline before the first character.

for every other character other than blank, newline and tab flag turns zero and if it gets blank, newline and tab flag is still zero but inspace==0 becomes TRUE then
inspace=1 and compiler makes newline is my logic correct ? sorry asking more n more just wanna know how exactly this executed ?

Thank you very much!