'Else without a previous if' - What Am I doing wrong?

Hello programmers!
I am new to c programming and just started a course 3 weeks ago, and now we need to make a project where it will be asking you a few things and then do the progress...
But I am having a few problems, could anybody help me please?

Code:

void PellerK(double *Produkt, double *Kvot){
  printf("Produkt eller Kvot?\n");    /*Asking to multiply or divide*/
  scanf("%lf %lf",&Produkt,&Kvot);

if (PellerK == Produkt); {
printf("Produkten blir = %d\n");
}
else (PellerK == Kvot); {
printf("Kvoten blir = %d\n");
}

This part above is when I encounter my problem...
When I try to run this I get an error where it says;
'Else without a previous if' - What am I doing wrong? Please help me out

If you see that I am doing anything else which is wrong, please feel free to help me out with that aswell!

Drop the semicolons directly after the if condition and the else condition.

The correct syntax for "if-else" is:

Code:

if(argument)
{
    // ...
}
else
{
    // ...
}

Don't put an argument after "else".

Also, remove the semi-colon after the "if()" - it does not belong there.

Code:

scanf("%lf %lf",&Produkt,&Kvot);

"scanf()" expects an address of the variables you're scanning. The two variables you're storing to are pointers (already addresses), so you don't need the & before them.

> if (PellerK == Produkt);
Remove the trailing ;

> else (PellerK == Kvot);
An else doesn't have an expression.
What this is is the statement which is evaluated when the else part is taken.

Wow, Thanks for the great quick respond!
But when I remove the semicolons I get a new error...

"Error: expected ";" before "{" token"

Edit: I found out what I was doing wrong...

Once again, thanks for the quick resonse and the great answers!