Nested while and || operator

[ntdvs]

Please refer to this code:

#include <stdio.h>

int array[5];

int main( void )
{
   int ctr = 0,
       nbr = 0;

    printf("This program prompts you to enter 5 numbers\n");
    printf("Each number should be from 1 to 10\n");

    while ( ctr < 5 )
    {
        nbr = 0;
        while (nbr < 1 || nbr > 10)
        {
            printf("\nEnter number %d of 5: ", ctr + 1 );
            scanf("%d", &nbr );
        }

        array[ctr] = nbr;
        ctr++;
    }

    for (ctr = 0; ctr < 5; ctr++)
        printf("Value %d is %d\n", ctr + 1, array[ctr] );

    return 0;
}

How does the code filter the program to accept numbers 1 to 10 only if while (nbr < 1 || nbr > 10) validates both expressions as TRUE?

[Tclausex]

If Either is true, not both.

It says, if number read is less than 1 OR greater than 10, loop again and re-prompt and read in a new number. When the number is in range [1,10] then the loop exits.

[ntdvs]

If Either is true, not both.

It says, if number read is less than 1 OR greater than 10, loop again and re-prompt and read in a new number. When the number is in range [1,10] then the loop exits.

Yes, I think I got it now - If either of the statements is TRUE, the statement will loop with the same ctr value which is "1" the first time. Then when the statement is FALSE, which is when a number between 1 to 10 is entered, the loop will exit and go to the outer while statement where it stores the entered number in the array, and increments the counter of that outer while statement. Right?

[Tclausex]

Well, ctr is 0 to start with, but yes, that's the gist of it.

[ntdvs]

Well, ctr is 0 to start with, but yes, that's the gist of it.

Ah yes, ctr is 0, it's just +1 first at the inner while loop. Thanks.