how can do a code for -1 to stop program?
example: Enter number of elements in array: -1Code:printf("Enter number of elements in array\n"); scanf("%d", &n); printf("Enter %d elements\n", n); for ( c = 0 ; c < n ; c++ ) scanf("%d", &array[c]);
output: End Program
Check the value before you use it, and react accordingly. Use an "if()". Is that what you're asking?
Assuming you are in the main function you can use a return statement, or the exit function.
The correct way to do it within another function is to return a failed value from the function back to main - You may want to save data before exiting the application.
An if statement is enough to check to see if -1 was entered. You should be checking to see if a Goldilocks value was entered (not too high, not too low) before trying to use it.
Code:int array[ARRAY_SIZE]; int n; puts("Enter number of elements in array (max 5 elements)"); if (1 == scanf("%d", &n) && 0 <= n && ARRAY_SIZE >= n) { int c; printf("Enter %d elements\n", n); for ( c = 0 ; c < n ; c++ ) { // TODO: Also needs checking to see if scanf succeeded scanf("%d", &array[c]); } } else if (-1 == n) { return EXIT_SUCCESS; } else { fputs("Unexpected input...", stderr); return EXIT_FAILURE; } return EXIT_SUCCESS;
Fact - Beethoven wrote his first symphony in C
This is my coding for swapping element. so how should i input the -1 inside this code? i tried to use: if ( -1 == n) printf("end program"); but don't works.Code:#include <stdio.h> #include <conio.h> #include <stdlib.h> int main() { int array[100], num1, c, n, num2; printf("Enter number of elements in array\n"); scanf("%d", &n); printf("Enter %d elements\n", n); for ( c = 0 ; c < n ; c++ ) scanf("%d", &array[c]); printf("Enter the number to swap\n"); scanf("%d", &num1); printf("Enter the number to swap with\n"); scanf("%d", &num2); printf("%d is swap place with %d.\n", num1, num2); for (c = 0; c < n; c++) { if (array[c] == num1) { array[c] = num2; } else if (array[c] == num2) { array[c] = num1; } } printf("The new output will be\n"); for (c = 0; c < n; c++) printf("%d\n", array[c]); getch(); return 0; }
can anyone help me out?
"Didn't work" is not a satisfactory response -> I don't know what you want.
How about this:
And you may want to be careful using conio.h -> It's only available on some systems. If you are making the program for yourself, you are limiting where you can use. If you are submitting this program as an assignment, not all markers will have access to conio.h (Your program will not compile on there computer). All you are using it for is the getch at the end -> You can use getchar() instead.Code:printf("Enter number of elements in array\n"); scanf("%d", &n); if (-1 == n) { exit(0); }
Fact - Beethoven wrote his first symphony in C
