redefinition of input

**SDH** · 01-22-2013

I am trying to make a poker scoring code and am struggling a bit with the 'picture cards'. The user inputs the hand
for example 3c 7d 9h js ad
I have worked out nearly all of the source code, except straights that include jack queen king ace.
Is there anyway that when a user types in J the code will recognize it as 11, then queen as 12, etc etc. So from there I could still use the same code I have already made. Thank you for your help.
Here is the part of my code that works out the straight.

Code:

#include<stdio.h>
int main(void)
{   int c;
    int n;
    int count1[127] = {0};
    int count2[127] = {0};
    int count3 = {0};
    int i;
    int a;
    int temp;
    int j;
    int difference; 
    char array[5];
    char array1[5];
    n = 5;
     
     
    for (c = 0; c < n; c++) 
        scanf("%c%c ", &array1[c], &array[c]);
        getchar();
    for (i=0;i<n; i++)
    {
    for (i=0; i<4; i++)
   {
      for (j=i+1; j<5; j++)
      {
         if(array1[i] > array1[j]) {
            temp = array1[i];
            array1[i] = array1[j];
            array1[j] = temp;
         }
      }   
   }
    
   for(i=0;i<n-1;i++) 
    {
    difference=(array1[i+1]-array1[i]);
       {if ( difference == 1)   
        count3++;
       }  
    
   }
    if ( count3 == 4)
       printf("Straight ");

**Salem** · 01-22-2013

Code:

         if(array1[i] > array1[j]) {
            temp = array1[i];
            array1[i] = array1[j];
            array1[j] = temp;
         }

This only swaps the rank, not the suit.
So swapping 3c with 7d results in 7c and 3d

Use a struct to keep related data together.

Code:

struct card {
    char rank;
    char suit;
};

Then you can swap hand[i] and hand[j] (where hand is an array of card), using the method you have at the moment.

As for turning J into 11 etc, consider a separate function which reads a letter and returns a number.

Code:

if ( ch == 'J' ) rank = 11;
// and so on.

**SDH** · 01-22-2013

I understand what you have mentioned above and am working on correcting that. However I am a bit confused what you have wrote inside the if statment, ( ch == 'j' ). What is ch?

**Salem** · 01-22-2013

ch is the generic name (like foo) for the char you just read with scanf() or getchar()

**SDH** · 01-23-2013

I am so very close to finishing my programming but I still get the source to certain input from the user as different numbers. so when a user types in J the code will recognize it as 11, then queen as 12, etc etc. Any help will be greatly appreciated

**c99tutorial** · 01-23-2013

Save yourself the headaches and make some conversion functions to repesent cards as integers. Example:

Code:

int ch2rank(char chrank) {
    switch(toupper(chrank)) {
    case 'A': return 1;
    case '1': return 1;
    case '2': return 2;
    case '3': return 3;
    case '4': return 4;
    case '5': return 5;
    case '6': return 6;
    case '7': return 7;
    case '8': return 8;
    case '9': return 9;
    case '0': return 10;
    case 'J': return 11;
    case 'Q': return 12;
    case 'K': return 13;
    }
    return 0;
}

int ch2suit(char chsuit) {
    switch(toupper(chsuit)) {
    case 'S': return 1;
    case 'H': return 2;
    case 'D': return 3;
    case 'C': return 4;
    }
    return 0;
}

How would you use the functions? Convert some characters into the appropriate values:

Code:

printf("Enter a card in the format RS (R: rank, S: suit).\n");
char chrank, chsuit;
scanf(" %c %c", &chrank, &chsuit);
int rank = ch2rank(chrank);
int suit = ch2suit(chsuit);
printf("%c%c: --> (%d, %d)\n", chrank, chsuit, rank, suit);

Simply repeat this process for all cards entered. For example, given the input 3c 7d 9h js ad, the output is:

3c: --> (3, 4)
7d: --> (7, 3)
9h: --> (9, 2)
js: --> (11, 1)
ad: --> (1, 3)

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