Thread: simple If statement not working

%c, unlike his friend %d, does not eat the newline character (because it as a character).
As a result when you press the key F, then you hit enter too.
So, the 1st scanf will read the F and the 2nd one the enter.
The solution is to put a space just before %c. This makes scanf to eat the newline automatically.

I suggest you use a do - while loop, since no matter what you will ask for an input at first.

Code:

#include <stdio.h>

int main(void)
{
    char input;
    do{
          printf("Please input\n");
          scanf(" %c", &input);
    }while(....);
  
    return 0;
}

Originally Posted by loserone+_+

yeahh camelman was right u must using if && what it means AND,
AND means that the if variable integrated
|| means OR
OR means that the if variable is choice, think about that logic

Hmm... I always pictured it as AND being multiplication and OR being addition (testing for a non-zero result)

i.e.
All variables need to be 1 (or true) for the result to be non-zero in the following
a*b*c
or
a && b && c

And, only one of the variables need to be non-zero for the following to be non-zero
a+b+c
or
a || b || c

I don't know what you mean by "variable integrated"

This is just the way I picture it, so that it makes sense to me.

Please note that Boolean algebra is very different to conventional algebra and "AND" shouldn't be taken as literately multiplication, nor "OR" as literally addition.