Hello to all

This is my firts post and topic here and also I'm new and starter in C++

as you see in topic title here is the code oftranspose of sparse matrix

can anyone tell me completely what does program do line by line

i have an another easy algorithm but want to know how this works and anyone knows another way to find transpose of this matrix , its good to have it in topic

thanks a lot

Code:#include<stdio.h> #include<conio.h> // transpose for the sparse matrix void main() { clrscr(); int a[10][10],b[10][10]; int m,n,p,q,t,col; int i,j; printf("enter the no of row and columns :\n"); scanf("%d %d",&m,&n); // assigning the value of matrix for(i=1;i<=m;i++) { for(j=1;j<=n;j++) { printf("a[%d][%d]= ",i,j); scanf("%d",&a[i][j]); } } printf("\n\n"); //displaying the matrix printf("\n\nThe matrix is :\n\n"); for(i=1;i<=m;i++) { for(j=1;j<=n;j++) { printf("%d",a[i][j]); } printf("\n"); } t=0; printf("\n\nthe non zero value matrix are :\n\n"); for(i=1;i<=m;i++) { for(j=1;j<=n;j++) { // accepting only non zero value if(a[i][j]!=0) { t=t+1; b[t][1]=i; b[t][2]=j; b[t][3]=a[i][j]; } } } // displaying the matrix of non-zero value printf("\n"); printf("a[0 %d %d %d\n",m,n,t); for(i=1;i<=t;i++) { printf("a[%d %d %d %d \n",i,b[i][1],b[i][2],b[i][3]); } b[0][1]=n; b[0][2]=m; b[0][3]=t; q=1; // transpose of the matrix printf("\n\nthe transpose of the matrix :\n "); if(t>0) { for(i=1;i<=n;i++) { for(j=1;j<=t;j++) { if(b[j][2]==i) { a[q][1]=b[j][2]; a[q][2]=b[j][1]; a[q][3]=b[j][3]; q=q+1; } } } } printf("\n\n"); printf("a[0 %d %d %d\n",b[0][1],b[0][2],b[0][3]); for(i=1;i<=t;i++) { printf("a[%d %d %d %d\n",i,a[i][1],a[i][2],a[i][3]); } getch(); }