missing prototype ?

I did put in the function prototype, but it said missing ..

Code:

#include<stdio.h>


int fnDeterminePrice(int);
float fnCalc(float , int);
void fnPrintResult(float);
void fnMenu();


int main() 
{
	int iCode, iQty;
	float fPrice, fPay;


	fnMenu();


	printf("enter item code and quantity:");
	scanf("%d %d", &iCode,&iQty);


	fPrice = fnDeterminePrice( iCode);
	fPay = fnCalc( fPrice , iQty);


	fnPrintResult(fPay);


	return 0;
}


void fnMenu()
{
	printf("1:Nasi lemak , 2:mee, 3 : sushi ");
}


int fnDeterminePrice( int itemCode)
{
	float fPricing;
	switch (itemCode) 
	{ 
		case 1 : fPricing = 1.50; break; 
		case 2 : fPricing = 2.00; break;
		case 3 : fPricing - 3.40; break;
		default : fPricing = 0.00;
	}
	return (fPricing);
}


float fnCalc( float fitemPrice , int iQuantity ) 
{
	float total;
	total = fitemPrice * iQuantity ;
	return ( total);
}


void fnPrintResult( float fPayment )
{
	printf("the price is %.3f " , fPayment);
}

can someone tell me the mistakes ?
thank you

What's the exact error you're receiving? Copy it and paste it here.

Building slideshow3.obj.
C:\Users\Eric\Documents\Pelles C Projects\C4\slideshow3.c(27): warning #2027: Missing prototype for 'fnMenu'.
Done.


this is the error

That's certainly there. Something weird with Pelles C, like maybe you didn't save the file after you added the prototype?

Also, I get this warning:

Code:

foo.c:47:21: warning: expression result unused [-Wunused-value]
                case 3 : fPricing - 3.40; break;

ok..so it means that error is some kind of bug ?

ok..thanks .I have fix that

I would change the prototype and the definition to be:

Code:

void fnMenu(void)

The item in the declaration list:

Code:

void fnMenu();

just defines the return type but not the parameters. This was used in K&R C. I am not sure what the standard says about whether this is a "prototype" or not.

putting the void in it clear the error

thank you !

just defines the return type but not the parameters. This was used in K&R C. I am not sure what the standard says about whether this is a "prototype" or not.

Yes both are "prototypes" but one takes no arguments (void), the other can take an unspecified number of arguments. The following is legal in C.

Code:

int test();

int main()
{

   test();
   test(1);
   test(1, "HELLO");
}

int test(int one, char* two)
{
   return(0);
}

Jim

Originally Posted by pheininger

just defines the return type but not the parameters. This was used in K&R C. I am not sure what the standard says about whether this is a "prototype" or not.

Originally Posted by jimblumberg

Yes both are "prototypes" but one takes no arguments (void), the other can take an unspecified number of arguments.

No, the declaration without the void is not a function prototype.

Originally Posted by C99 Clause 6.7.5.3 Paragraph 14c

The empty list in a function declarator that is not part of a definition of that function specifies that no information about the number or types of the parameters is supplied.

Originally Posted by C99 Clause 6.2.1 Paragraph 2d

A function prototype is a declaration of a function that declares the types of its parameters.