trouble passing parameter to function

This is a discussion on trouble passing parameter to function within the C Programming forums, part of the General Programming Boards category; I'm having some difficulty compiling the following code. When I run Code: void list_dir (char * dir_name) { DIR * ...

  1. #1
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    Dec 2012
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    trouble passing parameter to function

    I'm having some difficulty compiling the following code. When I run

    Code:
     void list_dir (char * dir_name)
    {
        DIR * d;
        d = opendir (dir_name);
    .....
    }
    
    int main (int argc, char *argv[])
    {     
       list_dir (argv[1]);
        return 0;
    }

    my program compiles without issue, but when I try to pass a second parameter to the function of either argv[2] or *argv, the compiler is telling me too few parameters to function or expecting * when parameter is **, an example is....

    Code:
    void
    list_dir (char * dir_name, char * newz)
    {
        DIR * d;
      d = opendir (dir_name);
    .....
    }
    
    int main (int argc, char *argv[])
    {
        list_dir (argv[1], argv[2]);
        return 0;
    }

    Any suggestions on why the compiler doesn't accept how the second argument, argv[2], is being passed. Thanks!

  2. #2
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    looks correct to me. can you post the exact error message and the exact code rather than an excerpt. try to boil it down to a very simple example.

  3. #3
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    Is there a function prototype for list_dir before this?
    If so maybe it's different from the function definition.

  4. #4
    Algorithm Dissector iMalc's Avatar
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    Indeed, the important bit is in precisely what is different between the example you post here and the real code.
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