i have this piece of code which is decoding function for rice algorithm. which i pass as input is a binary file, which is encoded.
working of encoder:
the range of input in encoding fn is 0-255, and the encoder creates a combination of unary and binary, for example if i have 42, it is encoded as (010)011111- for the part in bracket it is 42 mod 8 written in binary, part except bracket is int(42/8) written in unary.the in bitfile the value 010011111 is written.
now when i decode the file, i read bit by bit from the file, and the following fn is used which i didnt coded but got online:
here k=3, which is the number of bits for remainder.
As i understand the unary part is decoded, but i dont see where the binary part is decoded. i dont understand how this piece of code works with input from the file. I have written for each of the decoding steps, the value for tmp and byte in the code i thought, but they are not right bc i am getting correct decoded values when i run the code, so i am not understanding some part of it. plz can anyone help me understand this code.
/* decode input file */
while ((bit = BitFileGetBit(bfpIn)) != EOF)
if (1 == bit)
byte++; //for ex. for 010011111, this part will read 5 1's, byte=00000101
/* finished unary portion */
tmp = byte << k; //tmp=00101000 ( 00000101 << 3)
if (EOF == BitFileGetBits(bfpIn, &byte, k))
/* unary was actually spare bits */
byte >>= (CHAR_BIT - k); /* leftt justify bits, byte= 00000000 */
byte |= tmp;// byte=00101000
fputc(byte, fpOut);//here we write 40 instead of 42? where are the remaining 3 bits? i dont get this
byte = 0;
If u want to see the whle code for encoder as well as decoder, it is attached