# Help with flawed algorithm?

This is a discussion on Help with flawed algorithm? within the C Programming forums, part of the General Programming Boards category; Originally Posted by qny If the user types "<SPACE> <4> <2> <SPACE> <ENTER>" this will not consume the <ENTER>. It ...

1. Originally Posted by qny
If the user types "<SPACE> <4> <2> <SPACE> <ENTER>" this will not consume the <ENTER>.
It presumes the user is not a drunken sod, at that time - true.

2. Lol actually, Adak, it worked! I Had to tweak it a bit. But now I found another bug, prolly the last one! The code below is the mathematical algorithm the matrix does... The only problem is with division - if I enter numbers to divide - any numbers - it will tell me it failed (failed = the sum is NOT an integer!)

Code:
``` switch (matrix[i][j])
{
case '+': matrix[i+1][j] = (matrix[i-1][j]) + (matrix[i+1][j]);
break;
case '-': matrix[i+1][j] = (matrix[i-1][j]) - (matrix[i+1][j]);
break;
case '*': matrix[i+1][j] = (matrix[i-1][j]) * (matrix[i+1][j]);
break;
case '/':  if ((matrix[i+1][j]) ==0 )
{
printf("There is a division by zero");
return 1;
}
if (((matrix[i-1][j] / matrix[i+1][j])%2)  != 0)
{
left=1;
}

if (left == 1 )
{
printf("There is a non-integer division");
return 1;
}

matrix[i+1][j] = (matrix[i-1][j]) / (matrix[i+1][j]);
break;
}```
I tried a few variations but none worked...

The %2 thingy doesn't work for some reason.... and it enters the "Non Integer division" all the time! Even if : 1/1-1

Suggestions?

3. Probably because both matrix[i-1][j] and matrix[i+1][j] are Integers. Any way around that, tho? To save only the division's output? I tried putting it into float but it won't work...

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