Ok so my professor wants us to produce binary numbers in the grid box that I just made. I am not sure how that works. The only hint he gave us is that it requires anif commandand it should work for 3 digit numbers as well since my grid box is not fixed. Where would I implement that if I want to produce a binary number for each cell? By the way I'm working with a 4 x 4 grid table

Code:void GridBox(int Row,int Col,int SizeX, int SizeY, int Color) { int q,k,m; char UpperLeft[2],UpperRight[2],LowerLeft[2],LowerRight[2]; char Vertical[2],Horizontal[2]; char UpperTee[2],LowerTee[2],LeftTee[2],RightTee[2]; char Cross[2]; _settextcolor(Color); UpperLeft [0] = 218; UpperRight[0] = 191; LowerLeft [0] = 192; LowerRight[0] = 217; Vertical [0] = 179; Horizontal[0] = 196; UpperTee[0] = 194; LowerTee[0] = 193; LeftTee [0] = 195; RightTee[0] = 180; Cross [0] = 197; UpperLeft [1] = '\0'; UpperRight[1] = '\0'; LowerLeft [1] = '\0'; LowerRight[1] = '\0'; Vertical [1] = '\0'; Horizontal[1] = '\0'; UpperTee [1] = '\0'; LowerTee [1] = '\0'; LeftTee [1] = '\0'; RightTee [1] = '\0'; Cross [1] = '\0'; // CORNERS _settextposition(Row,Col); _outtext(UpperLeft); _settextposition(Row,Col+(3+1)*SizeX); _outtext(UpperRight); _settextposition(Row+(1+1)*SizeY,Col); _outtext(LowerLeft); _settextposition(Row+(1+1)*SizeY,Col+(3+1)*SizeX); _outtext(LowerRight); // Horizontal Lines for ( q = 0; q < SizeY + 1 ; q++) { for ( k = 0; k < SizeX ; k++) { for ( m = 0; m < 3 ; m++) { _settextposition(Row+(1+1)*q,(Col+1)+(3+1)*k+m); _outtext(Horizontal); } } } // Vertical Lines for ( q = 0; q < SizeX + 1 ; q++) { for ( k = 0; k < SizeY ; k++) { for ( m = 0; m < 1 ; m++) { _settextposition((Row+1)+(1+1)*k+m,Col+(3+1)*q); _outtext(Vertical); } } } // Upper & LowerTee's for ( k = 0; k < SizeX - 1 ; k++) { _settextposition(Row,Col+(3+1)*k+3+1); _outtext(UpperTee); _settextposition(Row+(1+1)*SizeY,Col+(3+1)*k+3+1); _outtext(LowerTee); } // Right & Left Tee's for ( k = 0; k < SizeY - 1 ; k++) { _settextposition(Row+(1+1)*k+1+1,Col); _outtext(LeftTee); _settextposition(Row+(1+1)*k+1+1,Col+(3+1)*SizeX); _outtext(RightTee); } // Crosses for ( k = 0; k < SizeY - 1 ; k++) { for ( m = 0; m < SizeX - 1 ; m++) { _settextposition(Row+(1+1)*k+1+1,Col+(3+1)*m+3+1); _outtext(Cross); } } }